Question

I need help with showing work for elimination for 8x-3y=-16 and 5x+2y=-41​

Answer 1

The values of x and y in the given equations are x=-5 and y=-8

Therefore the solution is (-5,-8)

Explanation:

Given equations are
`8x-3y=-16\hfill (1)`

and
`5x+2y=-41\hfill (2)`

To solve the equations by elimination method :

Multiply the equation (1) into 2 we get

`24x-6y=-32\hfill (3)`

Multiply the equation (2) into 2 we get

`15x+6y=-123\hfill (4)`

Adding the equations (3) and (4) we get

16x-6y=-32

15x+6y=-123

___________

31x=-155

`=(-155)/(31)`

Therefore x=-5

Substitute x=-5 in equation (1) we get

8(-5)-3y=-16

-40-3y=-16

-3y=-16+40

[tex]y=\frac{24}{-3}[/rex]

Therefore y=-8

The values of x and y in the given equations are x=-5 and y=-8

Therefore the solution is (-5,-8)