Question

Daniel had 25 to spend at the fair if the admission to the fair to s 4 and the rides cost 1.50 each write an inequality that represent Daniels situation

Answer 1

Question:

Daniel had $25 to spend at the fair. If the admission to the fair is $4 and the rides cost $1.50 each, write an inequality that represent Daniels situation what is the greatest number of rides daniel can go on?

Answer:

The inequality that represents Daniel situation is:

`4 + 1.50x\leq 25`

The greatest number of rides Daniel can go is 14

Solution:

Daniel had $25 to spend at the fair

Total amount with Daniel = $ 25

Admission price = $ 4

Cost of 1 ride = $ 1.50

Let "x" be the number of rides

Then cost of "x" rides is 1.50x

Then, we frame a inequality as:

Admission price + cost of "x" ride
`\leq` 25

`4 + 1.50x\leq 25`

Here we used "less than or equal to" symbol, because he can spend maximum upto 25 dollars

Solve for "x"

`4 + 1.50x\leq 25\\\\1.50x \leq 25 -4\\\\1.50x\leq 21\\\\Divide\ both\ sides\ by\ 1.50\\\\x\leq 14`

Thus greatest number of rides is 14