Question

At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?

Answer 1

44,725kelvin

Step-by-step explanation:

best of luck!

Answer 2

447,25k

Step-by-step explanation:

According to the ideal gas law

`PV=nRT`

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

`T=(PV)/(nR)\\ \\T=(12,3L.1,95atm)/(0,654mol.0,082(L.atm/K.mol))\\ \\T=447,25K`