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Write


f(x) = 3x {}^(2) - 5x + 1
in the form of

a(x - h)^(2) + k
Help me please!​

1 Answer

4 votes

Work backwards: Expand the desired form to get


a(x-h)^2+k=a(x^2-2xh+h^2)+k=ax^2-2ahx+ah^2+k

Then
a=3,
-2ah=-5, and
ah^2+k=1, from which we get
h=\frac56 and
k=-(39)/(36)=-(13)/(12). So we end up with


3x^2-5x+1=3\left(x-\frac56\right)^2-(13)/(12)

Work forwards: Complete the square by writing


3x^2-5x+1=3\left(x^2-\frac53x\right)+1=3\left(x^2-\frac53x+(25)/(36)-(25)/(36)\right)+1

Now we have a perfect square trinomial:


x^2-\frac53x+(25)/(36)=x^2-2\frac56x+\left(\frac56\right)^2=\left(x-\frac56\right)^2

Finally,


3x^2-5x+1=3\left(x-\frac56\right)^2-(13)/(12)

same as before.

User Ceylan
by
7.6k points

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