Question

2nd term in a sequence is 13 and the term to term rule is add 6​

Answer 1

Explanation:

I think you want to find the sequence with given data.

Here we are given that:

Second term t_2 = 13 & common difference d = 6

`\because \: t_2 = t_1 + d \\ \therefore \: t_1 = t_2 - d = 13 - 6 = 7 \\ \: \: \: \: \: t_3 = t_2 + d = 13 + 6 = 19\\ \: \: \: \: \: t_4 = t_3 + d = 19 + 6 = 25 \\ \: \: \: \: \: t_5 = t_4 + d = 25 + 6 = 31 \\ \: \: \: \: \: t_6 = t_5 + d = 31 + 6 = 37 \\ \: \: \: \: thus \: for \: n \: terms\\\: \: \: \: \: t_n = t_1 +(n - 1) d \\`

Hence the required sequence is:

7, 13, 19, 25, 31, 37............""