Question

Solve This Using The Quadratic Formula: 3x^2+9x-6=0

Answer 1

Therefore either
`x = (-3+√(17))/(2)` or,
`x = (-3-√(17))/(2)`

Explanation:

`3x^2 +9x -6=0`
`x = (-b\pm√(b^2- 4ac) )/(2a)`

`\Leftrightarrow x = (-9\pm√(9^2- 4.3(-6)) )/(2.3)` here a = 3 ,b = 9 and c= -6

`\Leftrightarrow x = (-9\pm√(153) )/(6)`

`\Leftrightarrow x = (3(-3\pm√(17)) )/(6)`

`\Leftrightarrow x = (-3\pm√(17))/(2)`

Therefore either
`x = (-3+√(17))/(2)` or,
`x = (-3-√(17))/(2)`