Question

An electric field from a charge has a magnitude of 4.5 × 10^4 N/C at a certain location that points outward. If another charge with a magnitude of −2.0 × 10^−6 C is brought near it, what is the strength of the electrostatic force that acts on this charge and how do the two charges behave?

Answer 1

The strength of the electrostatic force acts on this charge is F = 0.09 N.

Step-by-step explanation:

• The electrostatic force is the force that occurs between two charged particles having a positive or negative charge which tends to attract or repel depends on the charged particle.

The force on the electric field can be calculated by using the formula,

E = F / q

F = -q
`*` E

Given q = - 2.0
`*` 10^-6, E = 4.5
`*` 10^4.

electrostatic force = (2.0
`*` 10^-6)
`*`(4.5
`*` 10^4)

F = 0.09 N.

• Since the charge q is negative, the force is exerted opposite to the direction of the field. The field is a positive charge but the charge as a negative charge.