Answer:
Option (a) is correct.
Explanation:
We know that area of the circle is
where r is the radius of the circle.
Let
![f(r)=\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/8hi58jlnzxjw205kbnn7zrodlh13yk9jnm.png)
Differentiate with respect to r
![f'(r)=\pi 2r^(2-1)=2\pi r](https://img.qammunity.org/2021/formulas/mathematics/high-school/akbesrsxs4t9hx4ps9qb9z839doghz91qj.png)
As
,
![f'(12)=2\pi (12)=24\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/pveb2domfyqx7o220pj67mpwcb33snyj0v.png)
Also, its given that
![\Delta r=0.01\,\,inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/zgpneupvobdcua24e2tpomm0952mk53r3d.png)
We know that as per linear approximation to estimate the resulting error,
![\Delta f(r)\approx f'(r)\,\Delta r](https://img.qammunity.org/2021/formulas/mathematics/high-school/cccg5pzth9evfnu2og20ate67romw1k03a.png)
Put
![f'(r)=24\pi\,,\,\Delta r=0.01 \,\,inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/r2lpzliiib2e17w9m8vquy1if2irbipvh5.png)
![\Delta f(r)\approx f'(r)\,\Delta r\\=(24\pi)(0.01)\\=0.24\pi\,\,square \,\,inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/lhfkle5j07vpgxql8v8ykd2pnzwnq2w52v.png)
Therefore,
the error is
![\pm 0.24\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/b7448vmk8xxycjqjd94rsezetdd81b0x1k.png)
So, option (a) is correct.