Question

What is the inverse of the given relation?
y=7x2 - 3

Answer 1

The inverse of the given relation is
`x=\sqrt{(y+3)/(7)}` .

Explanation:

Given:

y=7x² - 3

Now, to find the inverse of the given relation.

`y=7x^2-3`

So, adding both the sides by 3 we get:

`y+3=7x^2`

Now, dividing both the sides by 7 we get:

`(y+3)/(7) =x^2`

And, using square root on both the sides we get:

`\sqrt{(y+3)/(7)} =x`

Thus:

`x=\sqrt{(y+3)/(7)}`

Therefore, the inverse of the given relation is
`x=\sqrt{(y+3)/(7)}` .