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Two charges of magnitude q are separated by a distance d. Assuming there are no changes to anything else, but the charges are separated by 3 times their current distance, what will happen to the Coloumb force between them?

User Briddums
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1 Answer

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Answer:

The new force between charges becomes (1/9)th of the initial force.

Step-by-step explanation:

The electric force acting between two charges is given by :


F=(kq_1q_2)/(d^2)

k is the electrostatic constant

If the two charges are separated by 3 times their current distance, d' = 3d

We need to find the new Coulomb force between the charges. The new force is given by :


F'=(kq_1q_2)/(d'^2)


F'=(kq_1q_2)/((3d)^2)


F'=(1)/(9)* (kq_1q_2)/(d^2)


F'=(F)/(9)

So, the new force between charges becomes (1/9)th of the initial force.

User Yasirkula
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