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What is an equation for the line that passes through the points (1,3) and (-5,5)

User Fonic
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1 Answer

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Answer:

y=-1/3x+10/3

Explanation:

m=(y2-y1)/(x2-x1)

m=(5-3)/(-5-1)

m=2/-6

m=-1/3

y-y1=m(x-x1)

y-3=-1/3(x-1)

y=-1/3x+1/3+3

y=-1/3x+1/3+9/3

y=-1/3x+10/3

User Roge
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