Question

A Frisbee of radius 5 inches that is spinning on a person's finger makes 20.2 revolutions in 18 seconds. What is the angular speed of a point on the outer edge of the Frisbee? Use 3.14 as an approximation for pi and round your answer to the nearest hundredth.

Answer 1

Angular Speed=7.05 rad/s

Step-by-step explanation:

Given data

Total revolution r=20.2 revolutions

Time t=18 s

To find

Angular Speed

Solution

First we need not revolutions per second

So

=(20.2)/18

=1.1222 rev/s

`Angular Speed=(1.122rev/s)2\pi \\Angular Speed=7.05rad/s`