Question

The evaporation losses from a reservoir of constant surface area of 500 acres are 150 acre-ft per day. Of the outflow from the reservoir is 50 cfs, determine the change in the water level of the reservoir in a day without inflow.

Answer 1

0.498 ft/day

Step-by-step explanation:

given,

Surface area, A = 500 acres

evaporation loss, E = 150 acre-ft/day

out flow from reservoir = 50 cfs

= 50 x 60 x 60 x 24

= 4.32 x 10⁶ ft³/day

= 4.32 x 10⁶ ft².ft/day

=
`(4.32* 10^6)/(43560)\ Acre.ft/day`

= 99.17 acre-ft/day

total moment of the water= evaporation loss + outflow

= 150 + 99.17

= 249.17 acre-ft/day

change in water level per day

=
`(249.17)/(500)`

= 0.498 ft/day

There is loss of 0.498 ft water per day.