Answer:
q_enclosed = 759.57 nC
Step-by-step explanation:
A cylindrical shell of radius 7.00 cm and length 2.48 m has its charge uniformly distributed on its curved surface. The magnitude of the electric field at a point 15.3 cm radially outward from its axis (measured from the midpoint of the shell) is 36.0 kN/C.
Find the value of the net charge on the shell.
Given that Length L of the cylinder shell is 248 cm and the diameter d is 7.0 cm. We can approximate L >> d. This approximation concludes that the cylindrical shell is infinitely long, when we are examining the Electric fiel strength E from the ends of the shell.
Hence,
E = q_enclosed / 2*pi*ε_o *r*l
Where r = d / 2, then
q_enclosed = E*(2*π*r*l*ε_o)
q_enclosed = (36000)*(2*π*8.85*10^-12 *0.153*2.48)
q_enclosed = 759.57 nC