Answer:
Step-by-step explanation:
Potential energy of system of three protons kept on the vertices of an equilateral triangle of side 2 x 10⁻¹⁵ m
= k ( q₁q₂ / r₁₂ + q₂q₃/r₂₃ + q₁q₃ / r₁₃ )
= k x 3 q² / r
= 9 x 10⁹ x 3 x (1.6 x 10⁻¹⁹)² / 2 x 10⁻¹⁵
= 34.56 x 10⁻¹⁴ J
Potential at infinity is zero
so work done
= 34.56 x 10⁻¹⁴ J - 0
= 34.56 x 10⁻¹⁴ J