Answer:
The solution to the given functions f(x) and g(x) is 1
Therefore f(x)=g(x)=0 when x=1
Explanation:
Given that the functions f(x) and g(x) defined as below

and

To verify that the solution satisfies f(x)=g(x) :
Put x=1 in f(x) and g(x) we get



Therefore f(x)=0 when x=1
put x=1



Therefore g(x)=0 when x=1
Therefore f(x)=g(x)=0 when x=1
Therefore the solution to the given functions f(x) and g(x) is 1.