Question

A 5 kg block moving at 2.3 m/s makes a head-on elastic collision with a stationary block of mass 2.2 kg. Find the velocity of the 2.2 kg block. Answer in units of m/sA 5 kg block moving at 2.3 m/s makes a head-on elastic collision with a stationary block of mass 2.2 kg. Find the velocity of the 2.2 kg block. Answer in units of m/s

Answer 1

Answer: The velocity of the 2.2 kg block is 5.23 m/s

Step-by-step explanation:

To calculate the velocity of the 2.2 kg block after the collision, we use the equation of law of conservation of momentum, which is:

`m_1u_1+m_2u_2=m_1v_1+m_2v_2`

where,

`m_1` = mass of block 1 = 5 kg

`u_1` = Initial velocity of block 1 = 2.3 m/s

`v_1` = Final velocity of block 1 = 0 m/s

`m_2` = mass of block 2 = 2.2 kg

`u_2` = Initial velocity of block 2 = 0 m/s

`v_2` = Final velocity of block 2 = ?

Putting values in above equation, we get:

`(5* 2.3)+(2.2* 0)=(5.0* 0)+(2.2* v_2)\\\\v_2=((5* 2.3))/(2.2)=5.23m/s`

Hence, the velocity of the 2.2 kg block is 5.23 m/s