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For a line that has current 140 AA and a height of 8.0 mm above the ground, what magnetic field does the line produce at ground level? Express your answer in teslas.

2 Answers

6 votes

Final answer:

The magnetic field produced by a line carrying a current of 140 A and located 8.0 mm above the ground is approximately 0.0875 T at ground level.

Step-by-step explanation:

To determine the magnetic field produced at ground level by a line carrying a current of 140 A and located 8.0 mm above the ground, we can use the formula for the magnetic field produced by a long, straight wire:

B = μ₀ * (I / 2πd)

Where:

B is the magnetic field

μ₀ is the permeability of free space, approximately 4π x 10^(-7) T·m/A

I is the current

d is the distance from the wire

Substituting the given values into the formula, we get:

B = (4π x 10^(-7) T·m/A) * (140 A / 2π x 0.008 m)

Simplifying the expression, we find that the magnetic field at ground level is approximately 0.0875 T.

User Trang
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5.0k points
4 votes

Answer:

35 x 10^-7 Tesla

Step-by-step explanation:

current, i = 140 A

distance, r = 8 m

The formula for the magnetic field due to a straight long wire is given by


B=(\mu _(0))/(4\pi ) (2i)/(r)


B=(10^(-7)* 2* 140)/(8)

B = 35 x 10^-7 Tesla

Thus, the magnetic field is given by 35 x 10^-7 Tesla.

User Kristel
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5.2k points