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The function​ s(t) represents the position of an object at time t moving along a line. Suppose s1=105 and s3=149. Find the average velocity of the object over the interval of time [1,3].

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Answer:

The average velocity is 22.

Explanation:

It is given that the function​ s(t) represents the position of an object at time t moving along a line.

If a position function is s(t), then the average velocity of the object over the interval of time [a,b] is


\text{Average velocity}=(s(b)-s(a))/(b-a)

The average velocity of the object over the interval of time [1,3] is


\text{Average velocity}=(s(3)-s(1))/(3-1)


\text{Average velocity}=(s(3)-s(1))/(2)

It is given that s(1)=105 and s(3)=149. Substitute these values in the above formula.


\text{Average velocity}=(149-105)/(2)


\text{Average velocity}=(44)/(2)


\text{Average velocity}=22

Therefore, the average velocity is 22.

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