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Solve 4 square root of 3 = 8cos

User JALLRED
by
4.3k points

1 Answer

4 votes

Therefore
\theta = 30^\circ

Explanation:

Given,


4√(3 ) =8 cos \theta


\Leftrightarrow cos \theta =(4√(3) )/(8)


\Leftrightarrow cos \theta =(√(3) )/(2)


\Leftrightarrow cos \theta =cos 30^\circ


\Leftrightarrow \theta = 30^\circ

Therefore
\theta = 30^\circ

User Cantfindname
by
4.4k points