Question

A standing wave is created on a string of length 1.2 m. If the speed of the wave on the string is 60.0 m/s, what is the fundamental frequency?

Answer 1

25 Hz

Step-by-step explanation:

Length, L = 1.2 m

velocity, v = 60 m/s

The frequency of the fundamental is given by

f = v / 2L

f = 60 / ( 2 x 1.2)

f = 25 Hz

Thus, the fundamental frequency is 25 Hz.

Answer 2

Fundamental frequency in the string will be 25 Hz

Explanation:

We have given length of the string L = 1.2 m

Speed of the wave on the string v = 60 m/sec

We have to find the fundamental frequency

Fundamental frequency in the string is equal to
`f=(v)/(2L)`, here v is velocity on the string and L is the length of the string

So frequency will be equal to
`f=(v)/(2L)=(60)/(2* 1.2)=25Hz`

So fundamental frequency will be 25 Hz