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Ken invests 6,000 into two accounts one account earns 8% interest and the other earns 12% interest after one year his total interest earned from the two accounts totals $580 how much did ken invest in the 8%

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Answer: ken invested $3500 in the 8% account.

Explanation:

Let x represent the amount invested in the account earning 8% interest.

Let y represent the amount invested in the account earning 12% interest.

Ken invests 6,000 into two accounts one account earns 8% interest and the other earns 12% interest. This means that

x + y = 6000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the account earning 8%

I = (x × 8 × 1)/100 = 0.08x

Considering the account earning 12%

I = (y × 12 × 1)/100 = 0.12y

After one year, his total interest earned from the two accounts totaled $580 . This means that

0.08x + 0.12y = 580 - - - - - - - - - - 1

Substituting x = 6000 - y into equation 1, it becomes

0.08(6000 - y) + 0.12y = 580

480 - 0.08y + 0.12y = 580

- 0.08y + 0.12y = 580 - 480

0.04y = 100

y = 100/0.04

y = 2500

x = 6000 - y = 6000 - 2500

x = 3500

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