Question

A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magnitude of the electrostatic force between the particles.

Answer 1

0.47 N

Step-by-step explanation:

q1 = 3.4 x 10^-6 C

q2 = 2 x 10^-6 C

d = 17.5 cm = 0.175 m

The electrostatic force is given by

`F=(Kq_(1)q_(2))/(d^(2))`

`F=(9*10^(9)*3.4* 10^(-6)* 2* 10^(-6))/(0.175* 0.175)`

F = 0.47 N

Thus, the force is 0.47 N.