Question

What is the distance between the points (2,10) and (-6, 4) on the coordinate

plane?

it B) 5 units​

Answer 1

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is
`s=√((x_2-x_1)^2+(y_2-y_1)^2)` units

Let
`(x_1,y_1)` ,
`(x_2,y_2)` be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

`s=√((-6-2)^2+(4-10)^2)`

`=√((-8)^2+(-6)^2)`

`=√(8^2+6^2)`

`=√(64+36)`

`=√(100)`

`=10`

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units