Answer:
g/f(-3) = (1/29) * (-5+x)(2+x)
2/9 is NOT in the domain of g/f
Explanation:
First we will calculate f(-3):
f(-3) = 2-9*(-3) = 2-(-27) = 2+27 = 29
Therefore, g/f(-3) = (1/29) * (-5+x)(2+x)
Now we will find the values that are not in the domain of g/f:
g/f = [(-5+x)(2+x)]/(2-9x)
The denominator of g/f should not be equal to zero, hence:
2-9x ≠ 0 ⇒ 2≠9x⇒x≠2/9
Therefore, 2/9 is NOT in the domain of g/f