Question

Estimate the frequency of vibration of your arm.

Let the length of the arm be 0.59 m. Consider the arm as a simple pendulum and assume its center of mass is about 2/3 its length from the shoulder.

Answer 1

0.7945 Hz

Step-by-step explanation:

Data provided in the question:

Length of the arm = 0.59 m

Since the center of mass lies at about
`(2)/(3)` of its length

Thus,

Length of the simple pendulum =
`(2)/(3)` × 0.59 m = 0.3933 m

Now,

Frequency of vibration, f =
`(1)/(2\pi)\sqrt(g)/(l)`

Thus,

we have,

Frequency of vibration for the arm =
`(1)/(2\pi)\sqrt(9.8)/(0.3933)`

or

Frequency of vibration for the arm = 0.7945 Hz