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A chemist prepares a solution of copper(l) sulfate (CuSo4) by measuring out 11.7 g of copper(II) sulfate into a 350. mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution. Be sure your answer has the correct number of significant digits molL x 1

User Smasell
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1 Answer

1 vote

Answer:

0.209 mol/L

Step-by-step explanation:

Given data

  • Mass of copper(lI) sulfate (solute): 11.7 g
  • Volume of solution: 350 mL = 0.350 L

The molar mass of copper(Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:

11.7 g × (1 mol/159.61 g) = 0.0733 mol

The molarity of copper(Il) sulfate is:

M = moles of solute / liters of solution

M = 0.0733 mol / 0.350 L

M = 0.209 mol/L

User Michael Piankov
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