Question

A deck of 52 playing cards consists of 4 suits (Clubs, Diamonds, Hearts, and Spades) of 13 cards each (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King). A randomly chosen card is drawn. The probability it is an even number (2, 4, 6, 8, or 10) or Club is _____. (Answer with a reduced fraction.)

Answer 1

P(EUC) = 28/52 = 7/13

The probability it is an even number (2, 4, 6, 8, or 10) or Club is 7/13

Explanation:

Let P(EUC) represent the probability a randomly chosen card is drawn is an even number (2, 4, 6, 8, or 10) or Club

P(EUC) = N(EUC)/N(T) .......1

Where;

N(EUC) = number of even number (2, 4, 6, 8, or 10) or Club.

N(T) = total number of cards

Number of clubs = 13

After removing the clubs, out of the remaining Diamonds, Hearts, and Spades

the number even numbers = 5×3 = 15

N(EUC) = 13 + 15 = 28

N(T) = 52

From equation 1;

P(EUC) = 28/52 = 7/13

Answer 2

Answer:The answer is 5/52

Explanation:

The total number of even cards are 20. So the probability of getting an even number from the deck of cards is 5/13.

And the probability of getting a club is 1/4.

So, the final answer is (5/13)*(1/4)=5/52.