Answer:
![I_2 = 3.16 I_1](https://img.qammunity.org/2021/formulas/physics/college/g79ga7ybp04cs6ovx6onng5kl373nfhc3c.png)
Step-by-step explanation:
given,
Intensity radiated by black body= I₁
room temperature = 300 K
Intensity radiated, I₂ = ?
At temperature = T₂ = 400 K
now,
Intensity of radiation, I = σ T⁴
now,
![(I_1)/(I_2)=(T_1^4)/(T_2^4)](https://img.qammunity.org/2021/formulas/physics/college/5vmvlarr9dx92jmsbpqejjhjh5qe3kqo3e.png)
![(I_2)/(I_1)=(T_2^4)/(T_1^4)](https://img.qammunity.org/2021/formulas/physics/college/drdnoxvhuzeogncqdgqzeyw07i726x7n91.png)
![I_2=I_1(T_2^4)/(T_1^4)](https://img.qammunity.org/2021/formulas/physics/college/dm8djw53kb1khwu873or7z2ntfbk5vq8zu.png)
![I_2=I_1(400^4)/(300^4)](https://img.qammunity.org/2021/formulas/physics/college/rvozp65a34u2grlbbn3xppoc0q4vadr0di.png)
![I_2 = 3.16 I_1](https://img.qammunity.org/2021/formulas/physics/college/g79ga7ybp04cs6ovx6onng5kl373nfhc3c.png)
hence, Radiation Intensity at 400 K is equal to I₂ = 3.16 I₁