Step-by-step explanation:
Given that,
The mass of the object, m = 0.9 kg
Force constant, k = 170 N/m
Maximum speed of the object, v = 0.2 m/s
Solution,
(a) The angular frequency of the object is given by :



The time period is given by :


T = 0.45 seconds
(b) The maximum velocity of the object in shm is given by :

Amplitude,


A = 0.0145 m
(c) The maximum acceleration of the object is given by :



Therefore, this is the required solution.