If x = -2 and y = 3, by how much does 2y^2 - x exceed 2x^2 - y? A) 5 B) 11 C) 15 D) 27 E) 31

asked Oct 16, 2021 75.0k views

1 vote

If x = -2 and y = 3, by how much does 2y^2 - x exceed 2x^2 - y?

A) 5
B) 11
C) 15
D) 27
E) 31

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5 votes

Answer:

the answer is c

Explanation:

Steven Grant answered Oct 16, 2021

5.7k points

2 votes

Answer:

c.)15

Explanation:

use order of operations

Wilik answered Oct 20, 2021

by Wilik

5.9k points

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