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how many moles of cesium carbonate will be produced when 5.34 moles of cesium reacts with iron iii carbonate

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Answer:

2.67 moles of CsCO

Step-by-step explanation:

The balance chemical equation for given single replacement reaction is;

6 Cs + Fe₂(CO₃)₃ → 3 Cs₂CO₃ + 2 Fe

According to equation,

6 moles of Cs produced = 3 moles of Cs₂CO₃

So,

5.34 moles of Cs will produce = X moles of Cs

Solving for X,

X = 5.34 mol × 3 mol / 6 mol

X = 2.67 moles of CsCO

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