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Which system of equations below has no solution?

y = 4x + 5 and y = 4x – 5
y = 4x + 5 and 2y = 8x + 10
y = 4x + 5 and y = One-fourthx + 5
y = 4x + 5 and y = 8x + 10

User Mashiro
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2 Answers

3 votes

Answer:

y = 4x + 5 and y = 4x – 5 has no solution

Explanation:

User ZKK
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8.4k points
4 votes

Answer:

y = 4x + 5 and y = 4x – 5 has no solutions

y = 4x + 5 and y = One-fourthx + 5 has no solutions

Explanation:

For y = 4x + 5 and y = 4x – 5 slnce y = y then 4x + 5 must be = 4x - 5 if we add like terms

4x - 4x = -5 - 5 ➡0 = -10 doesn't make sense so first equation has no solution.

Do tge same with y = 4x + 5 and 2y = 8x + 10 since 2y is twice of y then 8x + 10 must be twice 4x + 5

If we simply multiply 4x + 5 by 2 we can clearly see that it is equal to 8x + 10 therefore the second equation has solution

Now for y = 4x + 5 and y = One-fourthx + 5

One-fourth of x = 1/4

again since y=y 4x +5 must be = 1/4x + 5 but that doesn't seem possible.

The answer would be first and third option y = 4x + 5 and y = 4x – 5 and y = 4x + 5 and y = One-fourthx + 5 has no solutions

User Im Useless
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