Question

the velocity of s free fall object is given by v=√2gh where v is the velocity (m/s) g is acceleration due to gravity (m/s^2), and h is the distance (m) fallen. if the object hits the surface with a velocity of 30m/sec and on the Earth the acceleration is g=9.81 m/s^2 , determine the height from which the object was dropped.

Answer 1

Therefore 45.87 m from which the object was dropped.

Explanation:

Given , the velocity of free fall object is given by
`v = √(2gh)` where v is the velocity (m/s) g is acceleration due to gravity (m/s²) and h is the the distance (m) fallen.

v = 30 m/s

g = 9.81 m/s²

`v = √(2gh)`

⇔v² = 2gh [ squaring both sides]

`\Leftrightarrow h =(v^2)/(2g)`

`\Leftrightarrow h =(30^2)/(2 * 9.81)`

`\Leftrightarrow h = 45.87`

Therefore 45.87 m from which the object was dropped.