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The radius of a hydrogen atom is 37 pm and its mass is 1.67 × 10-24 g.

What is the density of the atom in grams per cubic centimeter?

Assume the atom is a sphere with: volume: (4/3)3.14 x radius^3

User Siuying
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1 Answer

2 votes

Answer:

d = 7.88 g/ cm³

Step-by-step explanation:

Given data:

Radius of hydrogen atom = 37 pm

Mass of hydrogen atom = 1.67 × 10⁻²⁴ g

Density of hydrogen atom = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Volume:

(4/3) 3.14 × r³

1.33×3.14 × (37pm)³

4.19×50653 pm³

211537.1 pm³

211537.1/9.223 ×10¹⁸

2.12 ×10⁻²⁵ cm³

Now we will determine the density.

d = m/v

d = 1.67 × 10⁻²⁴ g / 2.12 ×10⁻²⁵ cm³

d = 7.88 g/ cm³

User Druxtan
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