If h(x) = 5 + x and k (x) = StartFraction 1 Over x EndFraction, which expression is equivalent to (k circle h) (x)?

Question

asked Jul 9, 2021 234k views

2 Answers

J Fabian Meier · Answer 1 · 2021-07-13T18:58:29+0000

Answer:

The equivalent expression to
$(k\circ h)(x)$ is
(1)/(5+x)

Therefore
$(k\circ h)(x)=(1)/(5+x)$

Explanation:

Given that the functions h is defined by h(x)=5+x

and k is defined by
k(x)=(1)/(x)

To find the composition of k and h that is
$(k\circ h)(x)$ :

$(k\circ h)(x)=k(h(x))$

=k(5+x)

=(1)/(5+x)

Therefore
$(k\circ h)(x)=(1)/(5+x)$

The equivalent expression to
$(k\circ h)(x)$ is
(1)/(5+x)