Question:
A local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday. There were 55 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Sunday?
Answer:
375 hamburgers and 320 cheese burgers were sold
Solution:
Let "a" be the number of hamburgers sold
Let "b" be the number of cheese burgers sold
Local hamburger shop sold a combined total of 695 hamburgers and cheeseburgers on Sunday
Therefore,
a + b = 695 ------------ eqn 1
There were 55 fewer cheeseburgers sold than hamburgers
Number of cheese burgers sold = number of hamburgers - 55
b = a - 55 --------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
a + a - 55 = 695
2a = 695 + 55
2a = 750
a = 375
Substitute a = 375 in eqn 2
b = 375 - 55
b = 320
Thus 375 hamburgers and 320 cheese burgers were sold