Question

Help this thing is due tomorrow and I have no idea what to do

Answer 1

11. Density of the piece of wood = 3000 g/cm³

12. Density of wooden block = 2 g/cm³. and it will not float in water.

13. Volume of the plastic ball should be 250 mL

14. Mass of the ice cube = 0.162 g

15. Volume of gasoline spilled is equal to 2000 mL

Step-by-step explanation:

11.

Formula:
`Density = (Mass)/(Volume)`

Given:

Mass of wood piece = 7500 g

Volume of wood piece = 2.5 cm³

Therefore,
`Density = (7500\ g)/(2.5\ cm^(3) ) = 3000\ g/cm^(3)`

Density of the piece of wood = 3000 g/cm³

12.

Formula:
`Density = (Mass)/(Volume)`

Given:

Dimensions of wooden block = length × width × height = 5 cm × 4 cm × 2 cm

Mass = 80.0 g

Volume of wooden block =
`L* W* H = 5* 4* 2 = 40 cm^3`

Therefore,
`Density = (80\ g)/(40\ cm^(3) ) = 2\ g/cm^(3)`

Density of wooden block = 2 g/cm³.

Density of water is equal to 1 g/cm³

2 g/cm³ > 1 g/cm³

Since density of wooden block is greater than the density of water, the piece of wood will not float in water. It will sink.

13.

Formula:
`Volume= (Mass)/(Density)`

Given:

Mass of the ball = 125 g

Density = 0.5 g/mL

Therefore,
`Volume = (125\ g)/(0.5\ g/mL ) = 250\ mL`

Volume = 250 mL

Volume of the plastic ball should be 250 mL

14.

Formula:
`Mass = Density* Volume`

Given:

Dimensions of ice cube = length × width × height = 3 cm × 3 cm × 3 cm

Density = 0.006 g/mL

Volume of ice cube =
`L* W* H = 3* 3* 3 = 27\ cm^3`

Since,

`1\ cm^3 = 1\ mL,\\\\ Volume = 27\ mL`

Therefore,
`Mass = (0.006\ g/mL)* (27\ mL) = 0.162\ g`

Mass of the ice cube = 0.162 g.

15.

Formula:
`Volume= (Mass)/(Density)`

Given:

Mass of gasoline = 1330 g

Density = 0.665 g/mL

Therefore,
`Volume = (1330\ g)/(0.665\ g/mL ) = 2000\ mL`

Volume = 2000 mL

Volume of gasoline spilled is equal to 2000 mL