Answer:
97.73%
Explanation:
Mean (μ) = 170
Standard deviation (σ) = 5
Assuming a normal distribution, for any observed value, X, the z-score is determined by:

For X = 180:

A z-score of 2 corresponds to the 97.73-th percentile of a normal distribution.
Therefore, the percentage of data that is less than 180 is 97.73%.