The function that gives Freedonia's carbon-dioxide emissions in million tons, E(t), t years from today:

Solution:
The rate of decrease of carbon dioxide each other = 35%
The quantity of carbon dioxide emitted this year = 40 million tons
Let the quantity of carbon dioxide emitted after t year = E(t) millions tons
Then, the function that gives Freedonia's carbon-dioxide emissions in million tons, E(t), t years from today is given by:

Where,
p is the quantity of carbon dioxide emitted this year
r is the rate of interest
t = number of years
Here,
p = 40 million tons
r = 35 %
Substituting the values we get,

Thus, quantity of carbon-dioxide emissions in million tons after t yaers is given by function
