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A website says that you’ll need 48 fifty-pound bags of sand to fill a sandbox that measure 8ft by 8ft by 1ft. How many bags would you need for a sandbox 6ft by 4ft by 1ft?

User Caveman
by
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2 Answers

4 votes

Answer:

18 bags

Explanation:

Both sandboxes have a height of 1 ft. Hence, we consider their areas.

Area of sandbox 1 =
8*8=64

Area of sandbox 2 = [tex]6\times4=24[tex]

64 square foot = 48 bags

24 square foot = [tex]\frac{48}{64} \times24=18[tex] bags

User Regetskcob
by
3.2k points
3 votes

Answer: 18 fifty-pound bags of sand will be needed.

Explanation:

The sandbox is in the shape of a cuboid. The formula for determining the volume of a cuboid is expressed as

Volume = L × W × H

The website says that you’ll need 48 fifty-pound bags of sand to fill a sandbox that measure 8ft by 8ft by 1ft. The volume of the sandbox would be

Volume = 8 × 8 × 1 = 64 ft³.

To find the number of many bags that you would need for a sandbox 6ft by 4ft by 1ft, we would find the volume first.

Volume = 6 × 4 × 1 = 24 ft³

Therefore,

If a 48 fifty-pound bags of sand will fill 64ft³ a sandbox,

Then x fifty-pound bags of sand will fill 24ft³ a sandbox.

x = (24 × 48)/64 = 18

User Mishan
by
4.1k points