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In bioligy class cher is viewing cells with a microscope. cell h measures 8.76x10^-3 microns in diameter and cell v measures 2.19x10^-5 microns in diameter. how many tines larger is the bigger cell than the smaller cell?

1 Answer

2 votes

Answer:

Larger cell 400 times bigger cell than the smaller cell

Explanation:

Given:

diameter of the cell h =
8.76*10^(-3)

diameter of the cell v =
2.19 *10^(-5)

To Find:

How many tines larger is the bigger cell than the smaller cell?

Solution:

The cell h with diameter
8.76* 10^(-3) is larger and the cell v with diameter
2.19 * 10^(-5) is small. To find the number of times it is larger, we can divide the larger cell diameter by smaller cell diameter

=>
(8.76* 10^(-3))/(2.19 * 10^(-5))

=>
\frac{8.76* 10^ {-3} * 10^(5)}{2.19 }

=>
\frac{8.76* 10^ {(-3+5)}}{2.19 }

=>
(8.76* 10^2)/(2.19 )

=>
(876)/(2.19)

=> 400

Larger cell is the bigger cell than the smaller cell by 400 times

User Naing Linn Aung
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