Question

all my points! Calculate the change in free energy if 1.12 moles of Nal is dissolved in water at 25.0°C.​

Answer 1

Free energy change is -7.500248 kJ/mol

Step-by-step explanation:

If we have the enthalpy change and entropy change, we can find the free energy change using the equation,

ΔG = ΔH - TΔS

Temperature in K = 25°C + 273 = 298 K

ΔH for NaI = -7.50 kJ/mol

ΔS for NaI = 74 J/K mol = 0.074 kJ/K mol

Plugin the above values in the equation, we will get,

ΔG = -7.5 kJ/mol - 0.074 kJ/K mol / 298 K

= -7.5 kJ/mol - 0.000248 kJ/mol

= -7.500248 kJ/mol

Answer 2

Free energy change is -7.500248 kJ/mol

Step-by-step explanation:

If we have the enthalpy change and entropy change, we can find the free energy change using the equation,

ΔG = ΔH - TΔS

Temperature in K = 25°C + 273 = 298 K

ΔH for NaI = -7.50 kJ/mol

ΔS for NaI = 74 J/K mol = 0.074 kJ/K mol

Plugin the above values in the equation, we will get,

ΔG = -7.5 kJ/mol - 0.074 kJ/K mol / 298 K

= -7.5 kJ/mol - 0.000248 kJ/mol

= -7.500248 kJ/mol