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Nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. What force must be exerted on a nail with a circular tip of 1.00 mm diameter to create a pressure of 3.00×109Nm2?

User Anselm
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1 Answer

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Answer:

236 N.

Step-by-step explanation:

Pressure = Force/Area

P = F/A

F = P×A...................... Equation 1

Where P = pressure, A = Area of the surface in contact, F = Force exerted on the nail.

A = πd²/4............................ Equation 2

Where d = diameter, π = pie

Given: d = 1.00 mm = 0.001 m, π = 3.14

Substitute into equation 2

A = (0.001)²3.14/4

A = 7.85×10⁻⁷ m²

Also, P = 3.00×10⁹ N/m²

Substitute these values into equation 1

F = (3.00×10⁹)(7.85×10⁻⁷)

F = 2.36×10²

F = 236 N.

Hence the force exerted = 236 N.

User David Miller
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