Question

Calcium dissolved in the ocean is used by marine organ- isms to form CaCO3(s) in skeletons and shells. When the organisms die, their remains fall to the bottom. The amount of calcium carbonate that can be dissolved in seawater depends on the pressure. At great depths, where the pressure exceeds about 414 atm, the shells slowly.

Answer 1

Calcium dissolved in the ocean is used by marine organisms to form calcium carbonate in skeletons and shells. The amount of calcium carbonate that can be dissolved in seawater depends on the pressure. Ocean acidification can adversely affect the formation of calcium carbonate shells.

Step-by-step explanation:

Calcium dissolved in the ocean is used by marine organisms to form calcium carbonate (CaCO3) in skeletons and shells. When these organisms die, their remains fall to the bottom of the ocean. The amount of calcium carbonate that can be dissolved in seawater depends on the pressure, with greater depths having higher pressure. At depths exceeding about 414 atm, the shells slowly dissolve.

The formation of calcium carbonate in marine organisms' shells is part of the carbon cycle in the ocean. Carbon dioxide (CO2) from the atmosphere dissolves in seawater and combines with calcium ions to form calcium carbonate. Over time, these sediments contribute to the formation of limestone, which is the largest carbon reservoir on Earth.

Ocean acidification, caused by the increased absorption of CO2 by the ocean, can impact the ability of marine organisms to form calcium carbonate shells.

Answer 2

h = 1.403x10⁴ ft

Step-by-step explanation:

first, the missing part of the question is the following:

"This reaction prevents all the Eart h's calcium from being tied up as insoluble CaCO3(s) at the bottom of the sea. Estimate the depth (in feet) of water that exerts a pressure great enough to dissolve seashells."

Now, to calculate the depth in feet, of the water, we need to use the correct expression to this. As we are talking about the sea pressure and depth we need to use the hydrostatic pressure expression which is:

P = dgh (1)

Where:

P: Pressurre (In Pa or Kg/m.s²)

g: gravity acceleration (m/s²) = 9.81 m/s²

d: density of the water (g/mL or kg/m³) = 1000 kg/m³

h: height or depth (in m, which later will be converted to feet).

From (1), we can solve for h:

h = P/dg (2)

So, before we put the values in the expression, we need to convert the units of pressure to Pa:

P = 414 atm * 1.01325 Pa = 4.195x10⁷ Pa (1 Pa = 1 kg/m.s²)

Now, replacing the values in (2):

h = 4.195x10⁷ kg/m.s² / 9.81 m/s² * 1000 kg/m³ (All units but meters, cancels out)

h = 4,276.25 m

But we need this value in ft, and in 1 m we have 3.28 ft so:

h = 4,276.25 * 3.28

h = 14,026.1 ft or 1.403x10⁴ ft