Question

I really need helP!!!

Answer 1

Her fastest speed was 4 miles per hour.

Explanation:

Step 1; To calculate the different speeds we need to divide the times walked by the distances traveled in those time. Speed is given by distance divided by time. So to calculate the different speeds, we have to calculate it at points where the line isn't straight and changes. In the given graph there are 4 different speeds. 0 - 1 hour was the first speed, 1 - 1
`(1)/(2)` hours was the second speed, 1
`(1)/(2)` - 2 hours was the third speed and the final and fourth speed was from the
`2^(nd)` and
`4^(th)` hour.

Step 2; In the first period i.e. from 0 hours to 1 hour, Elena travels 3 miles in 1 hour. So speed was the miles traveled divided by the 1 hour it was traveled in. So speed was
`(3)/(1)` miles per hour = 3 miles per hour.

In the second period i.e. from 1 hour to 1
`(1)/(2)` hours, she has traveled 0 miles. So her speed was 0/1
`(1)/(2)` which equals 0. So she was at rest for half an hour after the first hour of walking. So speed during that period = 0 miles in that period.

During the third period i.e. from 1
`(1)/(2)` hours to 2 hours, she has traveled 2 miles in a period of half an hour. So her speed was the 2 miles traveled divided by the
`(1)/(2)` hour she traveled it in. So her speed was
`(2)/((1)/(2) )` which equals 4 miles per hour. So speed between 1
`(1)/(2)` hours and 2 hours = 4 miles per hour.

During the last period, Elena travelled 4 miles in 2 hours. So her speed was the 4 miles she covered by the 2 hours she covered it in. So her speed was
`(4)/(2)` miles per hour. So speed in between the
`2^(nd)` and
`4^(th)` hour = 2 miles her hour.

Step 3; Now we have to identify the fastest she walked between her four speeds. Her walking speeds were 3 miles per hour, 0 miles per hour, 4 miles per hour, 2 miles per hour. So her fastest speed was 4 miles per hour between the 1
`(1)/(2)` hours and 2 hours.