Answer:
26.56°
Step-by-step explanation:
given,
horizontal distance travel by the ant = 2 m
vertical distance travel by the ant = 1 m
angle of the ant above the initial point = ?
using trigonometric function
![tan \theta = (h)/(x)](https://img.qammunity.org/2021/formulas/physics/college/6ijfxa0wimkddjjrhh0xchcanwf1j1s77s.png)
θ is the angle of the ant form initial position
h is the height on the wall
x is the horizontal distance covered by the ant
![tan \theta = (1)/(2)](https://img.qammunity.org/2021/formulas/physics/college/t6amadqq456nm1b4km3xcoc3gk6juvfdwj.png)
![\theta =tan^(-1)(0.5)](https://img.qammunity.org/2021/formulas/physics/college/wa1zr42g8zfgwxdphg27clwl1nkegrkz87.png)
![\theta =26.56^0](https://img.qammunity.org/2021/formulas/physics/college/as32mduxjull36rforsq9cxzo9y7bggl74.png)
hence, the angle made by the ant from the initial position is equal to 26.56°