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A technical machinist is asked to build a cubical steel tank that will hold 230L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001m.

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Answer:

0.613 meters is the smallest possible inside length of the tank.

Step-by-step explanation:

Length of the cubical steel tank =- l

Volume of the cube =
l^3

Volume of cubical steel tank =
230 L = 230* 0.001 m^3


1 L = 0.001 m^3


V=l^3


230* 0.001 m^3=l^3

Solving of l :


l=0.6127 m\approx 0.613 m

0.613 meters is the smallest possible inside length of the tank.

User Tmilar
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