Answer:
Half life is given by
t1/2 = 136.3s
Step-by-step explanation:
Peaction Half-life:
The Half-life of a reaction is the time it takes for the reactant concentration to drop to half its original concentration.
For a second order reaction
the time it takes is given by
t1/2 = 1/(k×[A]○
Where k = rate constant and
[A]○ = initial concentration
Therefore
k = 7.53×109 M–1s–1 at a
[ClO]○ its initial concentration = 1.81×10-8 M.
t1/2 = 1/(7.53×109 × 1.81×10-8 )
t1/2 = 136.3 s