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Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00nC is on the x -axis at x= 3.00cm. Point P is on the y-axis at y = 4.00cm. a. Calculate the electric fields E→1 and E→2 at point P due to the charges q1 and q2.Express your answer in terms of the unit vectors i^, j^. b. Use the results of part (a) to obtain the resultant field at P, expressed in unit vector form

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Answer:

(a) E1 = -28.1 × 10^3 j N/C

E2 = (6.48i + 8.64j) N/C

(b) E = (6.48i - 19.46j) N/C

The electric field due to charge q1 is directed along the y-axis and has only a y-component. The electric field due to charge q2 at point P has both x- and y-components. This field acts at a distance of 5.0cm from the q2.

The Pythagorean theorem was used to calculate this distance.

Step-by-step explanation:

The full solution can be found in the attachments below.

Thank you for reading.

Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00nC is on the-example-1
Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00nC is on the-example-2
User Shaheen Ghiassy
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